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If the two circles x^(2)+y^(2)+2gz+2fy=0...

If the two circles `x^(2)+y^(2)+2gz+2fy=0` and `x^(2)+y^(2)+2g'x+2f'y=0` touch each other then show that `f'g=fg'`

A

`fg=f^(1)g^(1)`

B

`fg^(1)=f^(1)g`

C

`f+g=f^(1)+g^(1)`

D

`f+f^(1)=g+g^(1)`

Text Solution

Verified by Experts

The correct Answer is:
B
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