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The equation of the heyperbola with its ...

The equation of the heyperbola with its transverse axis parallel to x-axis and its centre is ( -2,1) the length of transverse axis is 10 and eccentricity 6/5 is

A

`x^(2)-2y^(2)+18x+27=0`

B

`((x+2)^(2))/(25)-((y-1)^(2))/(9)=1`

C

`((x-3)^(2))/(6)-((y-2)^(2))/(9)=1`

D

`((x-2)^(2))/(16)-((y-3)^(2))/(19)=1`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • The equation of the hyperbola with is transverse axis is parallel to y-axis and its centre is (2,-3) the length of transverse axis is 12 and eccentricity 7/6 is

    A
    ` ((y+3)^(2))/( 6) -( ( x+2)^(2))/(3)=1 `
    B
    `((y-3)^(2))/( 36) +((x-2)^(2))/( 13) =1`
    C
    ` ((y+3)^(2))/( 9) -((x-4)^(2))/( 4) =1`
    D
    ` ((y+3)^(2))/( 36) -((x-2)^(2))/(13) =1`

  • The equation of the hyperbola with is transverse axis parallel to x-axis and its centre is (3,-2) the length of axes, are 8,6 is

    A
    ` ((x-3)^(2))/( 16) -( (y+2)^(2))/( 9) =1`
    B
    ` ((x+2)^(2))/( 25) -((y-1)^(2))/( 11) =1`
    C
    ` ((x-3)^(2))/( 6) -( ( y-2) ^(2))/( 9) =1`
    D
    ` ((x-2) ^(2))/( 16) -((y-3)^(2))/( 19) =1`

  • The equation of the hyperola with its transverse axis is parallel el to x-axis and its centre (3,-2) the length of axes are 8,6 is

    A
    `((x-3)^(2))/(16)-((y+2)^(2))/(9)=1`
    B
    `((x+2)^(2))/(25)-((y-1)^(2))/(11)=1`
    C
    `((x-3)^(2))/(6)-((y-2)^(2))/(9)=-1`
    D
    `((x-2)^(2))/(16)-((y-3)^(2))/(19)=1`

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