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Equation of the hyperbola with foci (+-2...

Equation of the hyperbola with foci (+-2 ,0) and eccentricity 3/2 is

A

`x^2/9-y^(2)/4=-1`

B

`x^(2)/(20)-y^(2)/(16)=-1`

C

`x^(2)/4-y^(2)/5=4/9`

D

`(9x^(2))/(20)-(9y^(2))/(16)=-1`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • The equation of the hyperbola whose foci are ( +- 5,0) and eccentricity 5/3 is

    A
    ` (x^(2))/( 9) -y^( 2)/( 16) =1`
    B
    ` ( x^(2) )/( 4) -( y^(2))/( 16) = 1`
    C
    ` (x^(2) )/( 9) +( y^(2)) /( 6) = 1 `
    D
    ` (x^(2))/( 4) +(y^(2))/( 16) = 1 `

  • The equation of the hyperbola whose focus is origin, eccentricity sqrt2 and directrix x+y+1=0 is

    A
    ` 15x^(2) -24xy + 8y^(2) +12x + 2y -19 =0 `
    B
    ` 2xy + 2x+2y +1=0`
    C
    `11x^(2) +24xy + 4y^(2) -74x - 48y + 99=0 `
    D
    ` 7x^(2) +12xy -2y^(2) -2x + 14y -22=0`

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