In a `Delta ABC`, it given that base = 12 cm and height = 5 cm. Its area is

Options

A. 60 `cm^(2)`
B. 30 `cm^(2)`
C. `15 sqrt(3) cm^(2)`
D. 45 `cm^(2)`

Answer

To find the area of triangle ABC with a base of 12 cm and a height of 5 cm, we can use the formula for the area of a triangle:

### Step-by-Step Solution:

1. **Identify the formula for the area of a triangle**:
The area \( A \) of a triangle can be calculated using the formula:
\[ A = \frac{1}{2} \times \text{base} \times \text{height} \]

2. **Substitute the given values into the formula**:
Here, the base \( b = 12 \) cm and the height \( h = 5 \) cm. Substituting these values into the formula gives:
\[ A = \frac{1}{2} \times 12 \, \text{cm} \times 5 \, \text{cm} \]

3. **Calculate the product of the base and height**:
First, calculate \( 12 \times 5 \):
\[ 12 \times 5 = 60 \, \text{cm}^2 \]

4. **Multiply by \(\frac{1}{2}\)**:
Now, take half of 60 cm²:
\[ A = \frac{1}{2} \times 60 \, \text{cm}^2 = 30 \, \text{cm}^2 \]

5. **Conclude the area**:
Therefore, the area of triangle ABC is:
\[ A = 30 \, \text{cm}^2 \]