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The lengths of three sides of a triangle...

The lengths of three sides of a triangle are 20 cm, 16 cm and 12 cm. The area of the triangle is

A

96 `cm^(2)`

B

120 `cm^(2)`

C

144 `cm^(2)`

D

160 `cm^(2)`

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The correct Answer is:
To find the area of a triangle with sides of lengths 20 cm, 16 cm, and 12 cm, we can use Heron's formula. Here’s how to calculate it step by step: ### Step 1: Identify the sides of the triangle Let the sides of the triangle be: - \( a = 20 \) cm - \( b = 16 \) cm - \( c = 12 \) cm ### Step 2: Calculate the semi-perimeter (s) The semi-perimeter \( s \) is calculated using the formula: \[ s = \frac{a + b + c}{2} \] Substituting the values: \[ s = \frac{20 + 16 + 12}{2} = \frac{48}{2} = 24 \text{ cm} \] ### Step 3: Apply Heron's formula Heron's formula for the area \( A \) of the triangle is given by: \[ A = \sqrt{s(s-a)(s-b)(s-c)} \] Now, we will calculate each term: - \( s - a = 24 - 20 = 4 \) - \( s - b = 24 - 16 = 8 \) - \( s - c = 24 - 12 = 12 \) ### Step 4: Substitute the values into Heron's formula Now substituting the values into the formula: \[ A = \sqrt{24 \times 4 \times 8 \times 12} \] ### Step 5: Calculate the product inside the square root First, calculate the product: \[ 24 \times 4 = 96 \] \[ 96 \times 8 = 768 \] \[ 768 \times 12 = 9216 \] ### Step 6: Take the square root Now, we find the square root: \[ A = \sqrt{9216} \] Calculating the square root gives: \[ A = 96 \text{ cm}^2 \] ### Final Answer The area of the triangle is \( 96 \text{ cm}^2 \). ---
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RS AGGARWAL-AREAS OF TRIANGLES AND QUADRILATERALS-Multiple Choice Questions (Mcq)
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  5. The base of an isosceles triangle is 6 cm and each of its equal sides ...

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  7. Each side of an equilateral triangle is 10 cm long. The height of the ...

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  8. The height of an equilateral triangle is 6 cm. Its area is

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  9. The lengths of the three sides of a triangular field are 40 m, 24 m a...

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  10. The sides of a triangle are in the ratio 5 : 12 : 13 and its perimeter...

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  11. The lengths of the three sides of a triangle are 30 cm, 24 cm and 18 c...

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  12. The base of an isosceles triangle is 16 cm and its area is 48 cm^(2). ...

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  13. The area of an equilateral triangle is 36 sqrt(3) cm^(2). Its perimete...

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  14. Each of the equal sides of an isosceles triangle is 13 cm and its base...

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  15. The base of a right triangle is 48 cm and its hypotenuse is 50 cm lon...

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  16. If the area of an equilateral triangle is 81 sqrt(3) cm^(2), find its ...

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