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4(a+b)-6(a+b)^2...

`4(a+b)-6(a+b)^2`

Text Solution

Verified by Experts

The correct Answer is:
`2(a+b)(2-3a-3b)`
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Simplify: 4ab(a-b)-6a^(2)(b-b^(2))-3b^(2)(2a^(2)-a)+2ab(b-a)

Simplify: (a+b)^^2(a-b)^^2(a^(^^)2-ab+b^(^^)2)(a^(^^)2+ab+b^(^^)2)(a^(^^)4+a^(^^)2b^(^^)2+b^(^^)4)(a^(^^)6+b^(^^)6)^(^^)2'

Knowledge Check

  • If a : b = 2: 5 , then ( 3a+ 4b) : (5a +6b) is equal to

    A
    `13//20`
    B
    ` 26//33`
    C
    ` 16//27`
    D
    ` 18//35`

  • Solve for a and b:2(a+b)-(a-b)=6,4(a-b)=2(a+b)-9

    A
    `a=3/4,b=1 3/4`
    B
    `a=1/2,b=1 1/2`
    C
    `a=1 3/4, b=3/4`
    D
    `a=3/2, b=3/4`

  • Find the sum of the expressions - 3a ^(2) + 2 ab - 4b^(2) and - 6a ^(2) + 4b.

    A
    `- 9a ^(2) - 4b ^(2) + 2 ab + 4b`
    B
    `9a ^(2) + 4b ^(2) + 6 ab`
    C
    `- 9 a ^(2) - 4b ^(2) - 2 ab - 4 b`
    D
    None of the above

    • Similar Questions

    Explore conceptually related problems

    The product (a+b)(a-b)(a^(2)-ab+b^(2))(a^(2)+ab+b^(2)) is equal to: a^(6)+b^(6)(b)a^(6)-b^(6)(c)a^(3)-b^(3)(d)a^(3)+b^(3)

    Simplify : (a+2b)+(a-4b+6c)-(5a-3b) .

    (2a+b)^2-6a-3b-4

    If a + b = 6 and a^(2) - b^(2) = 24 , then a - b = 4 .

    The product of 4a^(2),-6b^(2) and 3a^(2)b^(2) is

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