a(a+b-c) - bc...

`a(a+b-c) - bc`

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The correct Answer is:

`(a-c)(a+b)`

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RS AGGARWAL-FACTORISATION OF POLYNOMIALS -Exercise 3A

Factorise : px-5q-5x+pq
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Factorise : x^2+y-xy-x
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factorize (a) (3a-1)^2 - 6a + 2
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Factorise : (2x-3)^2-8x+12
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Factorise : a^3+a-3a^2 -3
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3ax-6ay-8by+4bx
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Factorise : abx^2+a^2x+b^2x +ab
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x^(3)-x^(2)+ax+x-a-1
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Factorise 2x+4y-8xy-1
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ab(x^(2)+y^(2))-xy(a^(2)+b^(2))
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factorize the given expression a^2+ab(b+1)+b^3
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factorize the given expression a^3+ab(1-2a)-2b^2
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factorize : 2a^2+bc-2ab-ac
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(a x+b y)^2+(b x-a y)^2
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a(a+b-c) - bc
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Factorise : a(a-2b-c)+2bc
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Factorise : a^2x^2+(ax^2+1)x+a
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factorize : ab(x^2+1)+x(a^2+b^2)
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factorize : x^2-(a+b)x+ab
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Factorize (x^2+1/x^2-2-3x+3/x)
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