Factorise a^3-12a(a-4)-64...

Factorise ` a^3-12a(a-4)-64`

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The correct Answer is:

`(a-4)(a-4)(a-4)`

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RS AGGARWAL-FACTORISATION OF POLYNOMIALS -Exercise 3E

Expand (i) (3x+2)^3 (ii) (3a+(1)/(4b))^3 (iii) (1+(2)/(3)a)^3
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Expand (i) (5a-3b)^3 (ii)(3x-(5)/(x))^3 (iii) ((4)/(5)a-2)^3
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Factorize: 8a^3+27 b^3+36 a^2b+54 a b^2
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Factorize: 64 a^3-27 b^3-144 a^2b+108 a b^2
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Factorise 1+(27)/(125)a^3+(9a)/(5)+(27a^2)/(25)
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Factorize: 125 x^3-27 y^3-225 x^2y+135 x y^2
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Factorise a^3x^3-3a^2bx^2+3ab^2x-b^3
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Factorise (64)/(125)a^3-(96)/(25)a^2+(48)/(5)a-8
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Factorise a^3-12a(a-4)-64
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evaluate using suitable identities 1 . (99)^3 2. (103)^3
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