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Show that the diagonals of a parallel...

Show that the diagonals of a parallelogram divide it into four triangles of equal area.

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GIVEN A ||gm ABCD. Its diagonals AC and BD intersect at O.
TO PROVE `ar(triangleOAB)=ar(triangleOBC)`
`=ar(triangleOCD)=ar(triangleOAD)`

PROOF Since the diagonals of a ||gm bisect each other, we have
`OA=OC and OB=OD`.
Also, a median of a triangle divides it into two `triangle` of equal area.
Now, in `triangle`ABC, BO is the median.
`therefore ar(triangleOAB)=ar(triangleOBC)." "...(i)`
In `triangleABD,AO` is the median.
`therefore ar(triangleOAB)=ar(triangleOAD)." "...(ii)`
In `triangleACD,DO` is the median.
`therefore ar(triangleOAD)=ar(triangleOCD)." "...(iii)`
From (i), (ii) and (iii), we get
`therefore ar(triangleOAB)=ar(triangleOBC)." "...(i)`
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