Show that a median of a triangle divides it into two triangles of equal area.

The median of a triangle divides it into two

If A(4,-6),B(3,-2) and C(5,2) are the vertices of $ABC, then verify the fact that a median of a triangle ABC divides it into two triangles of equal areas.

As we know studied that a median of a triangle divides it into triangles of equal areas. Verify this result for Delta ABC whose vertices are A (4,-6), B(3,-2) and C (5,2).

Assertion (A) : If ABCD is a rhombus whose one angle is 60^(@) then the ratio of the lengths of its diagonals is sqrt3 : 1 Reason (R ) : Median of a triangle divides it into two triangle of equal area.

Consider the following statements in respect of any triangle I. The three medians of a triangle divide it into six triangles of equal area. II. The perimeter of a triangle is greater than the sum of the lengths of its three medians. Which of the statements given above is/are correct ?

A diagonal of a parallelogram divides it into two triangles of equal area.

Each diagonal of a |gm divides it into two triangles of the same area

Asserion (A) : The diagonals of a ||gm divide it into four triangle of equal area. Reason (R ) : A diagonal of a ||gm divides it into two triangle of equal area.

Show that the diagonals of a parallelogram divide it into four triangles of equal area.