Home
Class 9
MATHS
The base BC of Delta ABC is divided at D...

The base BC of `Delta ABC` is divided at D, so that `BD=1/2DC`. Prove that `ar(Delta ABD)`=`1/3ar(Delta ABC)`

Text Solution

Verified by Experts

Let E be the midpoint of DC. Then,
`BD = DE = EC = (1)/(3)BC`.
Join AD and AE.
In `triangleABE,` AD is a median and so `ar(triangleABD)=ar(triangleADE)`.
In `triangleADC,` AE is a median and so `ar(triangleADE)=ar(triangleAEC)`.
`therefore ar(triangleABD)=ar(triangleADE)=ar(triangleAEC)=(1)/(2)ar(triangleABC)`.
Promotional Banner

Topper's Solved these Questions

  • AREAS OF PARALLELOGRAMS AND TRIANGLES

    RS AGGARWAL|Exercise MULTIPLE-CHOICE QUESTIONS (MCQ)|32 Videos
  • AREAS OF PARALLELOGRAMS AND TRIANGLES

    RS AGGARWAL|Exercise ASSERTION & REASON TYPE|5 Videos
  • AREAS OF PARALLELOGRAMS AND TRIANGLES

    RS AGGARWAL|Exercise ASSERTION & REASON TYPE|5 Videos
  • AREAS OF TRIANGLES AND QUADRILATERALS

    RS AGGARWAL|Exercise Multiple Choice Questions (Mcq)|16 Videos

Similar Questions

Explore conceptually related problems

The base BC of Delta ABC is divided at D, so that BD=(1)/(2)DC. Prove that ar(Delta ABD)=(1)/(3)ar(Delta ABC)

D is a point on the base BC of Delta ABC.AD is produced upto E such that DE = AD. Prove that: area of Delta BCE = " area of " Delta ABC

ABCD is a trapezium in which AB I I DC. DC is produced to E such tha t CE= AB, prove that ar( Delta ABD) = ar( Delta BCE).

Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at O. Prove that ar( Delta AOD) = ar( Delta BOC).

ABCD is a trapezium with AB||DC. A line parallel to AC intersects AB at X and BC at Y. Prove that ar( Delta ADX) = ar( Delta ACY).

In the same figure, Delta ABC and Delta DBC are on the same base BC . If AD is intersects BC at O, prove that (ar(Delta ABC))/(ar (Delta DBC))=(AO)/(DO)

In the given figure, Delta ABC and Delta DBC have the same base BC. If AD and BC intersect at O, prove that (ar(DeltaABC))/(ar(Delta DBC))=(AO)/(DO)

In Delta ABC,AD and BE are altitudes.Prove that (ar(Delta DEC))/(ar(Delta ABC))=(DC^(2))/(AC^(2))

In the given figure,Delta ABC and Delta DBC are on the same base BC.If AD intersects BC at O , prove that (ar(Delta ABC))/(ar(Delta DBC))=(AO)/(DO)

In figure, ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE intersects BC at F, show that ar( Delta BDE) = 1/4 ar( Delta ABC)

RS AGGARWAL-AREAS OF PARALLELOGRAMS AND TRIANGLES -Exercise 11
  1. O is the any point on diagonal PR of parallelogram PQRS. Prove that Ar...

    Text Solution

    |

  2. In the adjoining figure, the diagonals AC and BD of a quadrilateral AB...

    Text Solution

    |

  3. The vertex A of triangle ABC is joined to a point D on the side BC. Th...

    Text Solution

    |

  4. D is the midpoint of side BC of triangleABC and E is the midpoint of ...

    Text Solution

    |

  5. In trapezium ABCD, AB || DC and L is the mid-point of BC. Through L, a...

    Text Solution

    |

  6. In the adjoining figure, ABCD is a quadrilateral. A line through D, p...

    Text Solution

    |

  7. In the adjoining figure, triangle ABC and triangleDBC are on the same ...

    Text Solution

    |

  8. ABCD is a parallelogram in which BC is produced to E such that CE = BC...

    Text Solution

    |

  9. A point E is taken on the side BC of a parallelogram ABCD. AE and DC a...

    Text Solution

    |

  10. P, Q, R, S are respectively the midpoints of the sides AB, BC, CD and ...

    Text Solution

    |

  11. किसी त्रिभुज ABC की मधिकाएँ CD और BE एक दूसरे को O पर कटती है , तो अन...

    Text Solution

    |

  12. The base BC of Delta ABC is divided at D, so that BD=1/2DC. Prove that...

    Text Solution

    |

  13. In the adjoining figure, BD||CA, E is the midpoint of CA and BD =(1)/(...

    Text Solution

    |

  14. The given figure shows a pentagon ABCDE.EG drawn parallel to DA meets ...

    Text Solution

    |

  15. In figure, CD || AE and CY || BA. Prove that ar (DeltaCBX) = ar (Delta...

    Text Solution

    |

  16. In the adjoining figure, the point D divides the sides of triangleABC ...

    Text Solution

    |

  17. In a trapezium ABCD, AB || DC, AB = a cm, and DC = b cm. If M and N ar...

    Text Solution

    |

  18. ABCD is a trapezium in which AB || DC, AB = 16 cm and DC = 24 cm. If E...

    Text Solution

    |

  19. In figure X and Y are the mid-points of AC and AB respectively, QP || ...

    Text Solution

    |

  20. In figure, ABCD and AEFD are two parallelograms. Prove that ar (DeltaP...

    Text Solution

    |