The area of trapezium ABCD in the given figure is

Options

A. `62 cm^(2)`
B. `93 cm^(2)`
C. `124 cm^(2)`
D. `155 cm^(2)`

Answer

C

Explanation

ar(trap. ABCD)=ar(sq. AECD)`+ar(triangleCEB)`
`[(8xx8)+((1)/(2)xx15xx8)]cm^(2)=(64+60)cm^(2)=124cm^(2)`.