In the given figure, ABCD and ABEF are parallelograms such that ar(quad. EABC) ` 17 cm^(2)` and ar(||gm ABCD) `= 25 cm^(2)`. Then `ar(triangleBCF)` = ?

Options

A. `4cm^(2)`
B. `4.8cm^(2)`
C. `6 cm^(2)`
D. `8cm^(2)`

Answer

D

Explanation

||gm ABCD and ||gm ABFE being on the same base and between the same parallels,
we have:
ar(||gm ABFE)=ar(||gm ABCD)=25 `cm^(2)`.
`ar(triangleBCF)=ar("||gm ABFE")-ar("quad. EABC")=(25-17)cm^(2)=8cm^(2)`.