In a `||^(gm)` `ABCD`, if `P` and `Q` are midpoints of `AB` and `CD` respectively and ar(||^(gm) ABCD) `= 16 cm^(2)` then ar `(||^(gm)` APQD) = ?

Options

A. `8 cm^(2)`
B. `12 cm^(2)`
C. `6 cm^(2)`
D. `9 cm^(2)`

Answer

A

Explanation

Let the distance between AB and CD be h cm. Then, ar(||gm APQD)`=AP xx h = (1)/(2)xx AB xx h =(1)/(2)` ar(||gm ABCD)
`=((1)/(2)xx16)cm^(2)= 8cm^(2)`.