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Choose the correct answer in each of the following questions:
`sec^(2)10^(@)-cot^(2)80^(@)=?`

A

1

B

0

C

`(3)/(2)`

D

`(1)/(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( \sec^2(10^\circ) - \cot^2(80^\circ) \), we can follow these steps: ### Step 1: Rewrite \(\cot(80^\circ)\) We know that: \[ \cot(80^\circ) = \tan(90^\circ - 80^\circ) = \tan(10^\circ) \] Thus, we can rewrite \(\cot^2(80^\circ)\) as: \[ \cot^2(80^\circ) = \tan^2(10^\circ) \] ### Step 2: Substitute into the expression Now we can substitute this back into the original expression: \[ \sec^2(10^\circ) - \cot^2(80^\circ) = \sec^2(10^\circ) - \tan^2(10^\circ) \] ### Step 3: Use the Pythagorean identity We know from trigonometric identities that: \[ \sec^2(\theta) - \tan^2(\theta) = 1 \] for any angle \(\theta\). Therefore, we can apply this identity: \[ \sec^2(10^\circ) - \tan^2(10^\circ) = 1 \] ### Final Answer Thus, the value of \( \sec^2(10^\circ) - \cot^2(80^\circ) \) is: \[ \boxed{1} \] ---

To solve the expression \( \sec^2(10^\circ) - \cot^2(80^\circ) \), we can follow these steps: ### Step 1: Rewrite \(\cot(80^\circ)\) We know that: \[ \cot(80^\circ) = \tan(90^\circ - 80^\circ) = \tan(10^\circ) \] Thus, we can rewrite \(\cot^2(80^\circ)\) as: ...
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