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How many natural numbers less than 1000 ...

How many natural numbers less than 1000 can be formed from the digits 0, 1, 2, 3, 4, 5 when a digit may be repeated any number of times?

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To solve the problem of how many natural numbers less than 1000 can be formed from the digits 0, 1, 2, 3, 4, and 5 (with repetition allowed), we will consider the numbers based on their digit count: 1-digit, 2-digit, and 3-digit numbers. ### Step-by-step Solution: 1. **Count 1-digit natural numbers:** - The digits available are 0, 1, 2, 3, 4, and 5. - However, since we are looking for natural numbers, we cannot include 0. - Therefore, the possible 1-digit natural numbers are: 1, 2, 3, 4, 5. - **Total 1-digit numbers = 5.** 2. **Count 2-digit natural numbers:** - The first digit (tens place) cannot be 0 (to ensure it's a 2-digit number). - Hence, the first digit can be any of the digits: 1, 2, 3, 4, or 5 (5 options). - The second digit (units place) can be any of the 6 digits (0, 1, 2, 3, 4, 5). - Therefore, the total number of 2-digit numbers can be calculated as: \[ \text{Total 2-digit numbers} = 5 \text{ (choices for the first digit)} \times 6 \text{ (choices for the second digit)} = 30. \] 3. **Count 3-digit natural numbers:** - The first digit (hundreds place) again cannot be 0. - So, the first digit can be any of the digits: 1, 2, 3, 4, or 5 (5 options). - The second digit (tens place) can be any of the 6 digits (0, 1, 2, 3, 4, 5). - The third digit (units place) can also be any of the 6 digits (0, 1, 2, 3, 4, 5). - Therefore, the total number of 3-digit numbers can be calculated as: \[ \text{Total 3-digit numbers} = 5 \text{ (choices for the first digit)} \times 6 \text{ (choices for the second digit)} \times 6 \text{ (choices for the third digit)} = 180. \] 4. **Calculate the total natural numbers less than 1000:** - Now, we sum up all the counts from the previous steps: \[ \text{Total natural numbers} = \text{Total 1-digit numbers} + \text{Total 2-digit numbers} + \text{Total 3-digit numbers} = 5 + 30 + 180 = 215. \] ### Final Answer: The total number of natural numbers less than 1000 that can be formed from the digits 0, 1, 2, 3, 4, and 5 is **215**. ---

To solve the problem of how many natural numbers less than 1000 can be formed from the digits 0, 1, 2, 3, 4, and 5 (with repetition allowed), we will consider the numbers based on their digit count: 1-digit, 2-digit, and 3-digit numbers. ### Step-by-step Solution: 1. **Count 1-digit natural numbers:** - The digits available are 0, 1, 2, 3, 4, and 5. - However, since we are looking for natural numbers, we cannot include 0. - Therefore, the possible 1-digit natural numbers are: 1, 2, 3, 4, 5. ...
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