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Find the number of different 4-letter words (may be meaningless) that can be formed from the letters of the word 'NUMBERS'.

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To find the number of different 4-letter words that can be formed from the letters of the word 'NUMBERS', we can follow these steps: ### Step 1: Identify the total number of distinct letters The word 'NUMBERS' consists of the letters: N, U, M, B, E, R, S. There are a total of 7 distinct letters. ### Step 2: Determine the number of letters to choose We need to form 4-letter words. Thus, we will choose 4 letters from the 7 distinct letters. ### Step 3: Use the permutation formula Since the order of the letters matters (as we are forming words), we will use the permutation formula: \[ P(n, r) = \frac{n!}{(n - r)!} \] where \( n \) is the total number of distinct letters, and \( r \) is the number of letters to choose. ### Step 4: Substitute the values into the formula Here, \( n = 7 \) and \( r = 4 \). Therefore, we need to calculate: \[ P(7, 4) = \frac{7!}{(7 - 4)!} = \frac{7!}{3!} \] ### Step 5: Calculate the factorials Now we calculate \( 7! \) and \( 3! \): - \( 7! = 7 \times 6 \times 5 \times 4 \times 3! \) - \( 3! = 3 \times 2 \times 1 = 6 \) ### Step 6: Simplify the expression Substituting back, we have: \[ P(7, 4) = \frac{7 \times 6 \times 5 \times 4 \times 3!}{3!} = 7 \times 6 \times 5 \times 4 \] ### Step 7: Perform the multiplication Now we calculate: \[ 7 \times 6 = 42 \] \[ 42 \times 5 = 210 \] \[ 210 \times 4 = 840 \] ### Final Answer Thus, the total number of different 4-letter words that can be formed from the letters of the word 'NUMBERS' is **840**. ---
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RS AGGARWAL-PERMUTATIONS-EXERCISE 8D
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  9. Find the number of permutations of the letters of the word 'ENGLISH'. ...

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  13. In how many arrangements of the word 'GOLDEN' will the vowels never o...

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  14. In how many different ways can the letters of the word MACHINE be a...

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  15. How many permutations can be formed by the letters of the word 'VOWELS...

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  16. How many numbers divisible by 5 and lying between 3000 and 4000 can be...

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  17. In an examination, there are 8 candidates out of which 3 candidates ha...

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