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Write the 4th term form the end in the e...

Write the 4th term form the end in the expansion of `(3/(x^(2))-x^(3)/6)^(7)`

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The correct Answer is:
`(35x^(6))/48`
rth term from the end `(n-r +2)th` term.
` :. 4th " term from the end " =(7-4+2)th` term = 5th term.
`T_(r+1) = (-1)^(r)*^(7) C _(r) (3/(x^(2)))^((7-r)) *((x^(3))/6)^(r) = (-1)^(r) xx .^(7)C_(r) xx 3 ^((7-2r)) xx 2^(-r) xx x^((5r-14)).`
`T _(5) = T_((4+1)) = (-1)^(4) xx .^(7)C_(4) xx 3^(-1) xx 2^(-4) xx x^(6) = .^(7)C_(3) xx 1/((3 xx 2^(4)))x^(6) = (35x^(6))/48.`
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