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1//x-1/y+1/z=4, 2/x+1/y-3/z=0, 1/x+1/y+1...

`1//x-1/y+1/z=4, 2/x+1/y-3/z=0, 1/x+1/y+1/z=2(x,y,z ne 0)`

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The correct Answer is:
`x=1/2,y=-1,z=1`
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