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int(sinx)/((sinx-cosx))dx=?...

`int(sinx)/((sinx-cosx))dx=?`

Text Solution

Verified by Experts

The correct Answer is:
`(1)/(2)x+(1)/(2)log|sinx-cosx|+C`
`I=int((sinx-cosx)+(sinx+cosx))/(2(sinx-cosx))dx`.
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