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int(cos2x)/((sinx+cosx)^(2))dx is equal ...

`int(cos2x)/((sinx+cosx)^(2))dx` is equal to

Text Solution

Verified by Experts

The correct Answer is:
`log|sinx+cosx|+C`
`I=int((cos^(2)x-sin^(2)x))/((sinx+cosx)^(2))dx=int((cosx-sinx))/((sinx+cosx))dx`.
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