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int(sin2x)/(1+bcosx)^(2)dx...

`int(sin2x)/(1+bcosx)^(2)dx`

Text Solution

Verified by Experts

The correct Answer is:
`(-2)/(b^(2)){:[log|a+bcosx|+(a)/((a+bcosx))]:}+C`
Put `(a+bcosx)=t."Then",cosx=((t-a))/(b)and-sin"x dx"=(1)/(b)dt`.
`:.I=-(2)/(b)*int(1)/(t^(2))((t-a)/(b))dt=-(2)/(b^(2))*int{(1)/(t)-(a)/(t^(2))}dt`.
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