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intlog10 x dx=...

`intlog_10 x dx=`

A

`(1)/(x)log_(e)10+C`

B

`(1)/(x)log_(10)e+C`

C

`x(logx-1)log_(e)10+C`

D

`x(logx-1)log_(10)e+C`

Text Solution

Verified by Experts

The correct Answer is:
D
`I=int(logx)/(log10)dx=(1)/(log_(e)10)*underset(I)((logx))*underset(II)(1)dx=(log_(10)e)*int{underset(I)((logx))*underset(II)(1)}dx`
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