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inte^(sinx)sin2x dx...

`inte^(sinx)sin2x dx`

A

`(2sinx)e^(sinx)+C`

B

`(2cosx)e^(sinx)+C`

C

`2e^(sinx)(sinx+1)+C`

D

`2e^(sinx)(sinx-1)+C`

Text Solution

Verified by Experts

The correct Answer is:
D
`I=2inte^(sinx)sinxcosxdx=2intunderset(I)(t)underset(II)e^(t)"dt, where "sinx=t`.
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