`intsec^-1xdx`

Options

A. `xsec^(-1)x+log|x+sqrt(x^(2)-1)|+C`
B. `xsec^(-1)x-log|x+sqrt(x^(2)-1)|+C`
C. `xsec^(-1)x+log|x-sqrt(x^(2)-1)|+C`
D. none of these

Answer

B

Explanation

Put `sec^(-1)x=t," so that "x=sect anddx=sect tantdt`.
`:." "I=intunderset(I)(t)underset(II)((sect tant))dt`.