Home
Class 12
MATHS
Let z and w be two complex numbers such ...

Let z and w be two complex numbers such that `|Z| <= 1, |w|<=1 and |z - iw| = |z-i bar w| = 2` and z equals

A

1 or i

B

i or -i

C

1 or -1

D

i or -1

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • COMPLEX NUMBERS

    MCGROW HILL PUBLICATION|Exercise SOLVED EXAMPLES LEVEL 2|1 Videos
  • COMPLEX NUMBERS

    MCGROW HILL PUBLICATION|Exercise SOLVED EXAMPLES LEVEL 3|1 Videos
  • COMPLEX NUMBERS

    MCGROW HILL PUBLICATION|Exercise QUESTIONS FROM PREVIOUS YEARS. B-ARCHITECTURE ENTRANCE EXAMINATION PAPER|17 Videos
  • CIRCLES AND SYSTEMS OF CIRCLES

    MCGROW HILL PUBLICATION|Exercise QUESTIONS FROM PREVIOUS YEARS. B-ARCHITECTURE ENTRANCE EXAMINATION PAPERS|17 Videos
  • DEFINITE INTEGRALS

    MCGROW HILL PUBLICATION|Exercise Questions from Previous Years. B-Architecture Entrance Examination Papers|18 Videos

Similar Questions

Explore conceptually related problems

Let Z and w be two complex number such that |zw|=1 and arg(z)-arg(w)=pi/2 then

Let z and omega be two complex numbers such that |z|<=1,| omega|<=1 and |z+omega|=|z-1vec omega|=2 Use the result |z|^(2)=zz and |z+omega|<=|z|+| omega|

Let z and omega be two complex numbers such that |z|=1 and (omega-1)/(omega+1) = ((z-1)^2)/(z+1)^2 then value of |omega-1| +|omega+1| is equal to____________

Let z and omega be two complex numbers such that |z|=1 and (omega-1)/(omega+1)=((z-1)/(x+1))^(2) . Then the maximum value of |omega + 1| is

Let z and omega be two complex numbers such that |z|lt=1,|omega|lt=1 and |z-iomega|=|z-i bar omega|=2, then z equals (a)1ori (b). ior-i (c). 1or-1 (d). ior-1

Let z and w be two complex number such that w = z vecz - 2z + 2, |(z +i)/(z - 3i )|=1 and Re (w) has minimum value . Then the minimum value of n in N for which w ^(n) is real, is equal to "_______."

Let zandw be two nonzero complex numbers such that |z|=|w| andarg (z)+arg(w)=pi Then prove that z=-bar(w) .

If z and w are two complex number such that |zw|=1 and arg(z)arg(w)=(pi)/(2), then show that bar(z)w=-i

MCGROW HILL PUBLICATION-COMPLEX NUMBERS -SOLVED EXAMPLES LEVEL 1
  1. Let za n dw be two non-zero complex number such that |z|=|w| and a r g...

    Text Solution

    |

  2. If |z|=1 and omega=(z-1)/(z+1) (where z in -1), then Re(omega) is

    Text Solution

    |

  3. Let z and w be two complex numbers such that |Z| <= 1, |w|<=1 and |z -...

    Text Solution

    |

  4. The complex numbers z = x + iy which satisfy the equation |(z-5i)/(z+5...

    Text Solution

    |

  5. The inequality |z-4| lt |z-2| represents

    Text Solution

    |

  6. If z1 and z2 are two complex numbers such that |(z1-z2)/(z1+z2)|=1, th...

    Text Solution

    |

  7. For any complex number z , find the minimum value of |z|+|z-2i|dot

    Text Solution

    |

  8. If x=2+ 5i then the value of x^3-5x^2+33x-19 is

    Text Solution

    |

  9. If z=x+iy and w=(1-iz)/(z-i), then |w|=1 implies that in the complex ...

    Text Solution

    |

  10. The real part of z = (1)/(1-cos theta + i sin theta) is

    Text Solution

    |

  11. If the imaginary part of (2z + 1)/(iz + 1) is -4, then the locus of th...

    Text Solution

    |

  12. Show that the area of the triagle on the argand plane formed by the co...

    Text Solution

    |

  13. If omega is a complex cube root of unity, then a root of the equation ...

    Text Solution

    |

  14. Let z1 and z2 be two non - zero complex numbers such that z1/z2+z2/z...

    Text Solution

    |

  15. If (1+x+x^2)^n=a0+a1x+a2x^2++a(2n)x(2n), find the value of a0+a6++ ,n ...

    Text Solution

    |

  16. Let z = |(1,1-2i,3+5i),(1+2i,-5,10i),(3-5i,-10i,11)|, then

    Text Solution

    |

  17. if (x+i y)^(1/3) = a+ib then (x/a) + (y/b) equals to

    Text Solution

    |

  18. If z epsilon C, the minimum value of |z| + |z-i| is attained at

    Text Solution

    |

  19. For all complex numbers z1, z2 satisfying |z1| =12 and |z2-3-4i|=5, ...

    Text Solution

    |

  20. If z lies on the circle |z-1|=1, then (z-2)/z is

    Text Solution

    |