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Suppose a and b are two different comple...

Suppose a and b are two different complete numbers such that `|a + sqrt(a^(2) - b^(2))| + | a - sqrt(a^(2) - b^(2))| = |a + b| + 4` then |a-b| is equal to _________

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To solve the problem, we need to analyze the given equation involving the complex numbers \( a \) and \( b \): \[ |a + \sqrt{a^2 - b^2}| + |a - \sqrt{a^2 - b^2}| = |a + b| + 4 \] ### Step 1: Simplify the expressions Let \( x = \sqrt{a^2 - b^2} \). Then we can rewrite the left-hand side of the equation as: \[ |a + x| + |a - x| \] ### Step 2: Use the property of absolute values Using the property of absolute values, we know: \[ |a + x| + |a - x| = 2 \max(|a|, |x|) \] This is because the sum of the absolute values of two terms can be expressed in terms of the maximum of those terms. ### Step 3: Rewrite the equation Now, we can rewrite our equation as: \[ 2 \max(|a|, |x|) = |a + b| + 4 \] ### Step 4: Analyze the term \( x = \sqrt{a^2 - b^2} \) Since \( x \) is defined as \( \sqrt{a^2 - b^2} \), we need to consider the conditions under which this expression is valid. For \( x \) to be real, we require \( a^2 \geq b^2 \). ### Step 5: Consider cases for \( |a| \) and \( |x| \) 1. **Case 1**: If \( |a| \geq |x| \), then: \[ 2|a| = |a + b| + 4 \] 2. **Case 2**: If \( |x| > |a| \), then: \[ 2|x| = |a + b| + 4 \] ### Step 6: Solve for \( |a - b| \) We will focus on the first case for simplicity. Rearranging gives us: \[ |a| = \frac{|a + b| + 4}{2} \] Now, we can express \( |a - b| \) in terms of \( |a| \) and \( |b| \): Using the triangle inequality: \[ |a - b| \leq |a| + |b| \] And the reverse triangle inequality: \[ |a - b| \geq ||a| - |b|| \] ### Step 7: Substitute and simplify From our earlier equation, we can express \( |b| \): Let \( |b| = |a| - 4 \) (assuming \( |a| \geq |b| \)). Then: \[ |a - b| = |a| + |b| = |a| + (|a| - 4) = 2|a| - 4 \] ### Step 8: Final calculation Substituting \( |a| = \frac{|a + b| + 4}{2} \) into our expression for \( |a - b| \): \[ |a - b| = 2\left(\frac{|a + b| + 4}{2}\right) - 4 = |a + b| + 4 - 4 = |a + b| \] ### Conclusion Thus, we find that: \[ |a - b| = 4 \]
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MCGROW HILL PUBLICATION-COMPLEX NUMBERS -SOLVED EXAMPLES (NUMERICAL ANSWER TYPE QUESTIONS )
  1. Radius of the circle |(z-1)/(z-3i)|=sqrt(2)

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  2. Suppose z(1), z(2), z(3) are vertices of an equilateral triangle with ...

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  3. Let m = Slope of the line |z + 3|^(2) - |z-3i|^(2) = 24, then m + 1.73...

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  4. If omega ne 1 is a cube root of unity, then (1)/(pi) sin^(-1) [(omega^...

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  5. ((1+sqrt(3)i)/(1-sqrt(3)i))^(181) + ((1-sqrt(3)i)/(1+sqrt(3)i))^(181) ...

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  6. Let z(1), z(2) be two complex numbers satisfying the equations |(z-4)/...

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  7. If z is a complex number, then the minimum value of |z - 2.8| + |z - 1...

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  8. If (3 z(1))/(5 z(2)) is purely imaginary, then |(2z(1)-z(2))/(2z(1) + ...

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  9. If omega ne 1 is a complex cube root of unity, then 5.23 + omega + ome...

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  10. If conjugate of a complex number z is (2+5i)/(4-3i), then |Re(z) + Im(...

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  11. Let z be a complex number such that Im(z) ne 0. "If a" = z^(2) + 5z + ...

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  12. Let z(k) = cos ((2kpi)/(7))+i sin((2kpi)/(7)),"for k" = 1, 2, ..., 6, ...

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  13. Let S = {z in C : |z - 2| = |z + 2i| = |z - 2i|} then sum(z in S) |z +...

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  14. Suppose z satisfies the equation z^(2) + z + 1 = 0."Let" omega = (z+(1...

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  15. Suppose omega ne 1 is cube root of unity. If 1(2-omega) (2-omega^(2)) ...

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  16. If z(1) and z(2) are two nonzero complex numbers and theta is a real n...

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  17. Eccentricity of the ellipse |z-4| + |z-4i| = 10 sqrt(2) is

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  18. Suppose a and b are two different complete numbers such that |a + sqrt...

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  19. Suppose z(1), z(2) and z(3) are three distinct complex numbers such th...

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  20. Let P be a point on the circle |z + 2 - 5i| = 6 and A be the point (4 ...

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