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Let z(1), z(2), z(3) be three non-zero c...

Let `z_(1), z_(2), z_(3)` be three non-zero complex numbers such that `z_(1) bar(z)_(2) = z_(2) bar(z)_(3) = z_(3) bar(z)_(1)`, then `z_(1), z_(2), z_(3)`

A

are vertices of an equilateral triangle

B

are vertices of an isosceles triangle

C

lie on a straight line

D

None of these

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The correct Answer is:
To solve the problem, we start with the given conditions for the complex numbers \( z_1, z_2, z_3 \): Given: \[ z_1 \overline{z_2} = z_2 \overline{z_3} = z_3 \overline{z_1} \] ### Step 1: Set the common value Let \( k \) be the common value such that: \[ z_1 \overline{z_2} = z_2 \overline{z_3} = z_3 \overline{z_1} = k \] ### Step 2: Express \( z_1, z_2, z_3 \) in terms of \( k \) From the first equation: \[ z_1 = \frac{k}{\overline{z_2}} \] From the second equation: \[ z_2 = \frac{k}{\overline{z_3}} \] From the third equation: \[ z_3 = \frac{k}{\overline{z_1}} \] ### Step 3: Take the modulus of the equations Taking the modulus of the equations, we have: \[ |z_1| |\overline{z_2}| = |k| \quad \Rightarrow \quad |z_1| |z_2| = |k| \] \[ |z_2| |\overline{z_3}| = |k| \quad \Rightarrow \quad |z_2| |z_3| = |k| \] \[ |z_3| |\overline{z_1}| = |k| \quad \Rightarrow \quad |z_3| |z_1| = |k| \] ### Step 4: Set the equations equal From the above equations, we can set: \[ |z_1| |z_2| = |z_2| |z_3| = |z_3| |z_1| \] ### Step 5: Cancel out \( |z_2| \) Assuming \( |z_2| \neq 0 \), we can cancel \( |z_2| \) from the first two equations: \[ |z_1| = |z_3| \] ### Step 6: Use the equality of moduli From the second and third equations, we also have: \[ |z_2| = |z_1| \] \[ |z_3| = |z_2| \] ### Step 7: Conclude that all moduli are equal Thus, we conclude: \[ |z_1| = |z_2| = |z_3| \] ### Step 8: Establish the distances Now, we can find the distances: \[ |z_1 - z_2|^2 = |z_1|^2 + |z_2|^2 - 2 \text{Re}(z_1 \overline{z_2}) = 2|z_1|^2 - 2 \text{Re}(k) \] \[ |z_2 - z_3|^2 = |z_2|^2 + |z_3|^2 - 2 \text{Re}(z_2 \overline{z_3}) = 2|z_2|^2 - 2 \text{Re}(k) \] \[ |z_3 - z_1|^2 = |z_3|^2 + |z_1|^2 - 2 \text{Re}(z_3 \overline{z_1}) = 2|z_3|^2 - 2 \text{Re}(k) \] ### Step 9: Equate the distances Since all moduli are equal, we find: \[ |z_1 - z_2| = |z_2 - z_3| = |z_3 - z_1| \] ### Conclusion Thus, the distances between the points are equal, which means that the points \( z_1, z_2, z_3 \) are the vertices of an equilateral triangle. ### Final Answer Therefore, \( z_1, z_2, z_3 \) are the vertices of an equilateral triangle. ---
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