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Find the equation of the ellipse whose a...

Find the equation of the ellipse whose auxilliary circle is the director circle of the ellipse `x^2/36+y^2/13=1` and the length of a latus rectum is 2 units.

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To find the equation of the ellipse whose auxiliary circle is the director circle of the ellipse \( \frac{x^2}{36} + \frac{y^2}{13} = 1 \) and the length of the latus rectum is 2 units, we can follow these steps: ### Step 1: Identify the parameters of the given ellipse The given ellipse is \( \frac{x^2}{36} + \frac{y^2}{13} = 1 \). From this, we can identify: - \( a^2 = 36 \) (so \( a = 6 \)) - \( b^2 = 13 \) (so \( b = \sqrt{13} \)) ### Step 2: Find the equation of the director circle The equation of the director circle for an ellipse is given by: \[ x^2 + y^2 = a^2 + b^2 \] Substituting the values of \( a^2 \) and \( b^2 \): \[ x^2 + y^2 = 36 + 13 = 49 \] Thus, the equation of the director circle is: \[ x^2 + y^2 = 49 \] ### Step 3: Understand the auxiliary circle of the new ellipse Let’s denote the new ellipse we need to find as \( \frac{x^2}{\alpha^2} + \frac{y^2}{\beta^2} = 1 \). The auxiliary circle of this ellipse has the equation: \[ x^2 + y^2 = \alpha^2 \] ### Step 4: Relate the auxiliary circle to the director circle Since the auxiliary circle of the new ellipse is equal to the director circle of the given ellipse, we have: \[ \alpha^2 = 49 \] This gives us: \[ \alpha = 7 \] ### Step 5: Use the length of the latus rectum to find \( \beta \) The length of the latus rectum \( L \) for an ellipse is given by: \[ L = \frac{2b^2}{a} \] We know from the problem that \( L = 2 \) units. Substituting the values we have: \[ 2 = \frac{2b^2}{\alpha} \] Substituting \( \alpha = 7 \): \[ 2 = \frac{2b^2}{7} \] Multiplying both sides by 7: \[ 14 = 2b^2 \] Dividing by 2: \[ b^2 = 7 \] ### Step 6: Write the equation of the ellipse Now that we have \( \alpha^2 = 49 \) and \( \beta^2 = 7 \), the equation of the ellipse is: \[ \frac{x^2}{49} + \frac{y^2}{7} = 1 \] ### Final Answer: The equation of the ellipse is: \[ \frac{x^2}{49} + \frac{y^2}{7} = 1 \] ---
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