Mahesh walks 20 metres towards North. He then left and walks 40 metres. He again turns left and walks 20 metres. Further, he moves 20 metres after turning to the right. How far is the from his original position ?

Options

A. 20m
B. 30 m
C. 50 m
D. 60 m

Explanation

To solve the problem step by step, let's break down Mahesh's movements and calculate his final position relative to his starting point.

### Step-by-Step Solution:

1. **Starting Point**: Mahesh starts at point O (0, 0).

2. **First Movement**: Mahesh walks 20 meters towards North.
- New position: (0, 20)

3. **Second Movement**: He then turns left (to the West) and walks 40 meters.
- New position: (0 - 40, 20) = (-40, 20)

4. **Third Movement**: He again turns left (to the South) and walks 20 meters.
- New position: (-40, 20 - 20) = (-40, 0)

5. **Fourth Movement**: He moves 20 meters after turning to the right (to the West).
- New position: (-40 - 20, 0) = (-60, 0)

6. **Calculating Distance from Original Position**:
- The original position is O (0, 0) and the final position is (-60, 0).
- The distance from the original position can be calculated using the formula for distance between two points:
\[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]
- Here, (x1, y1) = (0, 0) and (x2, y2) = (-60, 0).
- So, the distance is:
\[ \text{Distance} = \sqrt{(-60 - 0)^2 + (0 - 0)^2} = \sqrt{(-60)^2} = \sqrt{3600} = 60 \text{ meters} \]

### Final Answer:
Mahesh is **60 meters** away from his original position.