Suresh walks 20 metres North. Then he turns right and walks 30 m. Then he turns right and walks 35 m. Then he turns left and walks 15 m. Then he gains turns left and walks 15 m. In which direction and how many metres away is he from his original position ?

Options

A. 15m, West
B. 30m, East
C. 30 m, West
D. 45 m, East

Explanation

To solve the problem step by step, we will track Suresh's movements and determine his final position relative to his starting point.

### Step-by-Step Solution:

1. **Starting Point**: Let's assume Suresh starts at point O (0, 0) on a coordinate plane.

2. **First Movement**: Suresh walks 20 meters North.
- New position: O (0, 0) to A (0, 20).

3. **Second Movement**: He turns right (to the East) and walks 30 meters.
- New position: A (0, 20) to B (30, 20).

4. **Third Movement**: He turns right again (to the South) and walks 35 meters.
- New position: B (30, 20) to C (30, -15).
- (20 - 35 = -15 on the y-axis)

5. **Fourth Movement**: He turns left (to the East) and walks 15 meters.
- New position: C (30, -15) to D (45, -15).
- (30 + 15 = 45 on the x-axis)

6. **Fifth Movement**: He turns left (to the North) and walks 15 meters.
- New position: D (45, -15) to E (45, 0).
- (-15 + 15 = 0 on the y-axis)

7. **Final Position**: Suresh's final position is E (45, 0).

8. **Distance from Original Position**: To find the distance from the original position O (0, 0) to E (45, 0), we can use the distance formula:
- Distance = √[(x2 - x1)² + (y2 - y1)²]
- Distance = √[(45 - 0)² + (0 - 0)²] = √[45²] = 45 meters.

9. **Direction**: Since the final position E (45, 0) is on the positive x-axis, Suresh is 45 meters to the East of his original position.

### Conclusion:
Suresh is **45 meters East** from his original position.