In the following series, how many such odd numbers are there which are divisible by 3 or 5, then followed by odd numbers and then also followed by even numbers?
12, 19, 21, 3, 25, 18, 35, 20, 22, 21, 45, 46, 47, 48, 9, 50, 52, 54, 55, 56.

Options

A. Nil
B. One
C. Two
D. Three

Explanation

To solve the problem, we need to identify the odd numbers in the given series that are divisible by 3 or 5, and check if they are followed by another odd number and then an even number.

The series provided is:
12, 19, 21, 3, 25, 18, 35, 20, 22, 21, 45, 46, 47, 48, 9, 50, 52, 54, 55, 56.

### Step-by-step Solution:

1. **Identify Odd Numbers**:
The odd numbers in the series are:
- 19
- 21
- 3
- 25
- 35
- 21
- 45
- 47
- 9
- 55

2. **Check Divisibility by 3 or 5**:
Now, we check which of these odd numbers are divisible by 3 or 5:
- 19: Not divisible by 3 or 5
- 21: Divisible by 3
- 3: Divisible by 3
- 25: Divisible by 5
- 35: Divisible by 5
- 21: Divisible by 3
- 45: Divisible by 3 and 5
- 47: Not divisible by 3 or 5
- 9: Divisible by 3
- 55: Divisible by 5

The odd numbers that are divisible by 3 or 5 are: 21, 3, 25, 35, 45, 9, and 55.

3. **Check the Following Conditions**:
We now check if each of these numbers is followed by another odd number and then an even number:
- **21**: Followed by 3 (odd) and then 25 (odd) - does not satisfy.
- **3**: Followed by 25 (odd) and then 18 (even) - satisfies.
- **25**: Followed by 18 (even) - does not satisfy.
- **35**: Followed by 20 (even) - does not satisfy.
- **45**: Followed by 46 (even) - does not satisfy.
- **9**: Followed by 50 (even) - does not satisfy.
- **55**: Followed by 56 (even) - does not satisfy.

4. **Count the Valid Cases**:
The only odd number that satisfies the conditions is:
- 3 (followed by 25 (odd) and then 18 (even)).

Thus, there is only **1 valid odd number** that meets the criteria.

### Final Answer:
The total count of such odd numbers is **1**.