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The position of moving object at time 't...

The position of moving object at time 't', `x=2t^(3),` then find the acceleration.

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`x = 2t ^(3)`
`v = (dx)/(dt) = (d)/(dt) (2t ^(3))`
`v = 6t ^(2)`
Now, acceleration `a = (dv)/(dt) = (d)/(dt) ( 6t ^(2))`
`therefore a = 12 t`
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KUMAR PRAKASHAN-MOTION IN A STRAIGHT LINE -SECTION-C
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