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A particle, starting from rest, moves wi...

A particle, starting from rest, moves with constant acceleration `4 ms^(-2).` The distance travelled by the particle in `5^(th)` second is.

A

20 m

B

18 m

C

22 m

D

50 m

Text Solution

Verified by Experts

The correct Answer is:
B
Distance covered with constant acceleration a in .n. th speed
`d _(n) = v _(0) +a/2 (2n -1) , ` here `v _(0) =0, a = 4 ms ^(-2) , n =5`
`therefore d _(5) =0+ 4/2 (2 xx 5-1)`
`therefore d _(5) = 2 (9) =18m`
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Knowledge Check

  • A car starting from rest, moves some distance with constant acceleration 3 ms^(-2). Then it moves with constant deceleration 2 ms ^(-2) and finally becomes stationary. If the total time taken for the complete journey is 100 s, what was maximum velocity of the car e iu during the journey ?

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