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The displacement of particle with respec...

The displacement of particle with respect to time is `s = 3^(t3) - 7t^(2) + 5t + 8` where s is in m and t is in s, then acceleration of particle at t = ls is

A

`14 ms^(-2)`

B

`18 ms ^(-2)`

C

`32 ms^(-2)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C
`s =3t ^(3) + 7t ^(2) + 5t +8`
`therefore v = 9t ^(2) + 14 t +5`
`and a = 18 t + 14`
Now` t=1s`
`a (1) = 18 +14`
`therefore a (1) = 32 ms ^(-12`
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