At `27^(@)C` temperature, 36 gm glucose is in 1 litre aqueous solution has `pi = 4.98` bar. Find out concentration if `pi = 1.52` bar at same temperature.

Explanation

`pi = iCRT = CRT (because i=1" for glucose")`
`4.98 =(36)/(180)xx RT " "` ….(1)
`pi = C xx RT " "` …..(2)
Now, `("equation (1)")/("equation (2)")=(4.98)/(pi)=(36)/(180)xx(1)/(C )`
`therefore C = 0.061 mol L^(-1)`