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Let A be 3xx3 matrix such that A is orth...

Let A be `3xx3` matrix such that A is orthogonal idempotent then

A

A must be symmetric

B

det(A) =-I

C

A +`A^(-1) =1`

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the properties of the matrix \( A \) given that it is both orthogonal and idempotent. ### Step-by-Step Solution: 1. **Understanding Orthogonal Matrix**: A matrix \( A \) is orthogonal if \( A^T A = I \), where \( A^T \) is the transpose of \( A \) and \( I \) is the identity matrix. 2. **Understanding Idempotent Matrix**: A matrix \( A \) is idempotent if \( A^2 = A \). 3. **Combining Properties**: Since \( A \) is both orthogonal and idempotent, we can write: \[ A^T A = I \quad \text{(orthogonal)} \] \[ A^2 = A \quad \text{(idempotent)} \] 4. **Using Idempotent Property**: From the idempotent property \( A^2 = A \), we can substitute \( A \) into the orthogonal property: \[ A^T A = I \implies A^T A = A \quad \text{(since \( A^2 = A \))} \] 5. **Taking Transpose**: Taking the transpose of both sides of \( A^T A = I \): \[ (A^T A)^T = I^T \] Using the property of transpose, we have: \[ A^T A^T = I \implies A A^T = I \] 6. **Conclusion from Orthogonality**: Since both \( A^T A = I \) and \( A A^T = I \) hold true, this means \( A \) is indeed an orthogonal matrix. 7. **Identifying the Matrix**: Now, since \( A \) is both orthogonal and idempotent, we can conclude that: \[ A = I \] because the only orthogonal idempotent matrix in \( \mathbb{R}^{3 \times 3} \) is the identity matrix. 8. **Symmetry of Matrix**: Since \( A = I \), we can also state that \( A \) is symmetric because the identity matrix is symmetric: \[ A^T = A \] ### Final Answer: Thus, the matrix \( A \) is the identity matrix \( I \), and it is symmetric.
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