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If f(x) = x^(a) log x and f(0) = 0 then...

If `f(x) = x^(a) log x and f(0) = 0 ` then the value of `alpha` for which Rolle's theorem can be applied in [0,1] is

A

`-1`

B

`-1//2`

C

0

D

`1//2`

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The correct Answer is:
D
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If f(x)={(x^(alpha)logx , x > 0),(0, x=0):} and Rolle's theorem is applicable to f(x) for x in [0, 1] then alpha may equal to (A) -2 (B) -1 (C) 0 (D) 1/2

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