Home
Class 12
MATHS
Equation of normal to x= 2e^(t), y= e^(-...

Equation of normal to `x= 2e^(t), y= e^(-t) " at " t=0` is

A

`x + y-4=0`

B

`x+2y -4=0`

C

`2x-y-3=0`

D

`x-2y-3=0`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • APPLICATIONS OF DERIVATIVES

    MCGROW HILL PUBLICATION|Exercise Exercise ( LEVEL-1 SINGLE CORRECT ANSWER TYPE QUESTIONS)|45 Videos

  • APPLICATIONS OF DERIVATIVES

    MCGROW HILL PUBLICATION|Exercise Exercise ( LEVEL-2 SINGLE CORRECT ANSWER TYPE QUESTIONS)|38 Videos

  • APPLICATIONS OF DERIVATIVES

    MCGROW HILL PUBLICATION|Exercise Solved Examples ( NUMERICAL ANSWER TYPE QUESTIONS )|18 Videos

  • AREA BY INTEGRATION

    MCGROW HILL PUBLICATION|Exercise Question from Previous Years. B-Architecture Entrance Examination Papers|12 Videos

Similar Questions

Explore conceptually related problems

Find the equation of normal to the curve x = at^(2), y=2at at point 't'.

The equation of normal to the curve x=(1)/(t), y=t-(1)/(t)" at "t=2 is

Find the equation of normal to the curves x=t^(2),y=2t+1 at point

Equations of the tangent and normal to the curve x=e^(t) sin t, y=e^(t) cos t at the point t=0 on it are respectively

Find dy/dx , if x and y are connected parametrically by the equations, given below without eliminating the parameter: x=e^(t)cost,y=e^(t)sint" at "t=pi/2 .

The equation of the normal at the point t = (pi)/4 to the curve x=2sin(t), y=2cos(t) is :

Find the equations of the tangent and normal to the curve x = a sin 3t, y = cos 2 t " at " t = (pi)/(4)

Find the equations of the tangent and the normal to the curve x=a t^2,\ \ y=2a t at t=1 .

A curve is represented parametrically by the equations x=e^(t)cos t and y=e^(t)sin t where t is a parameter.Then The relation between the the parameter.t' and the angle a between the tangent to the given curve andthe x-axis is given by,t' equals