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If a variable plane in 3-dimensional spa...

If a variable plane in 3-dimensional space moves in such a way that the sum of the reciprocals of its intercepts on the x and y-axes exceeds the reciprocal of its intercept on the z-axis by 2, then all such planes will pass through the point:

A

(1/2, 1/2, -1/2)

B

(1/2, 1/2, 1/2)

C

(1/2, -1/2, -1/2)

D

(1/2, -1/2, 1/2)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given condition about the variable plane in 3-dimensional space. ### Step-by-Step Solution: 1. **Understanding the Plane Equation**: The equation of a plane that intercepts the x-axis at \( A \), the y-axis at \( B \), and the z-axis at \( C \) can be expressed as: \[ \frac{x}{A} + \frac{y}{B} + \frac{z}{C} = 1 \] 2. **Reciprocals of Intercepts**: The reciprocals of the intercepts are: \[ \frac{1}{A}, \quad \frac{1}{B}, \quad \text{and} \quad \frac{1}{C} \] 3. **Setting Up the Condition**: According to the problem, the sum of the reciprocals of the x and y intercepts exceeds the reciprocal of the z intercept by 2: \[ \frac{1}{A} + \frac{1}{B} = \frac{1}{C} + 2 \] 4. **Rearranging the Equation**: Rearranging the above equation gives: \[ \frac{1}{A} + \frac{1}{B} - \frac{1}{C} = 2 \] 5. **Finding a Common Point**: Let’s denote \( x_1 = 1 \), \( y_1 = 1 \), and \( z_1 = -1 \) as a point through which all such planes pass. We need to check if this point satisfies the condition derived: \[ \frac{1}{A} + \frac{1}{B} - \frac{1}{C} = 2 \] 6. **Substituting the Point**: Substitute \( x_1, y_1, z_1 \) into the plane equation: \[ \frac{1}{A} + \frac{1}{B} + \frac{-1}{C} = 2 \] This implies: \[ \frac{1}{A} + \frac{1}{B} = 2 + \frac{1}{C} \] 7. **Finding the Ratios**: From the condition, we can express the ratios: \[ \frac{1}{A} = k, \quad \frac{1}{B} = k, \quad \frac{1}{C} = k - 2 \] This gives us: \[ A = \frac{1}{k}, \quad B = \frac{1}{k}, \quad C = \frac{1}{k - 2} \] 8. **Conclusion**: Therefore, the point through which all such planes pass is: \[ \left( \frac{1}{2}, \frac{1}{2}, -\frac{1}{2} \right) \] ### Final Answer: The fixed point through which all such planes pass is: \[ \boxed{\left( \frac{1}{2}, \frac{1}{2}, -\frac{1}{2} \right)} \]
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