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If a+b+c!=0, the system of equations (b+...

If `a+b+c!=0,` the system of equations `(b+c)(y+z)-ax=b-c, (c+a)(z+x)-by=c-a` and `(a+b)(x+y)-cz=a-b` has

A

a unique solution

B

no solution

C

infinite number of solutions

D

finitely many solutions

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The correct Answer is:
A
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