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If a circle passes through the point (3,...

If a circle passes through the point `(3,4) ` and cuts the circle `x ^(2) + y ^(2) =a ^(2)` orthogonally, the equation of the locus of its centre is

A

`3x + 4y -a ^(2) =0`

B

`6x + 8y =a ^(2) +25`

C

`6x + 8y +a ^(2) + 25=0`

D

`3x + 4y =a ^(2) + 25`

Text Solution

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The correct Answer is:
To find the equation of the locus of the center of a circle that passes through the point (3, 4) and cuts the circle \(x^2 + y^2 = a^2\) orthogonally, we can follow these steps: ### Step 1: General Equation of the Circle The general equation of a circle can be expressed as: \[ x^2 + y^2 + 2gx + 2fy + c = 0 \] where the center of the circle is at the point \((-g, -f)\). ### Step 2: Circle Passing Through (3, 4) Since the circle passes through the point (3, 4), we can substitute these coordinates into the general equation: \[ 3^2 + 4^2 + 2g(3) + 2f(4) + c = 0 \] Calculating \(3^2 + 4^2\): \[ 9 + 16 + 6g + 8f + c = 0 \] This simplifies to: \[ 25 + 6g + 8f + c = 0 \quad \text{(1)} \] ### Step 3: Condition for Orthogonality For the two circles to intersect orthogonally, the following condition must hold: \[ 2g_1g_2 + 2f_1f_2 = c_1 + c_2 \] For the circle \(x^2 + y^2 = a^2\), we can rewrite it as: \[ x^2 + y^2 + 0x + 0y - a^2 = 0 \] Here, \(g_2 = 0\), \(f_2 = 0\), and \(c_2 = -a^2\). Substituting into the orthogonality condition: \[ 2g(0) + 2f(0) = c + (-a^2) \] This simplifies to: \[ 0 = c - a^2 \quad \Rightarrow \quad c = a^2 \quad \text{(2)} \] ### Step 4: Substitute \(c\) into Equation (1) Now, substituting \(c = a^2\) into equation (1): \[ 25 + 6g + 8f + a^2 = 0 \] Rearranging gives: \[ 6g + 8f = -25 - a^2 \quad \text{(3)} \] ### Step 5: Locus of the Center The center of the circle is at the point \((-g, -f)\). Replacing \(g\) with \(-x\) and \(f\) with \(-y\) (where \((x, y)\) is the center of the circle), we have: \[ 6(-x) + 8(-y) = -25 - a^2 \] This simplifies to: \[ -6x - 8y = -25 - a^2 \] Multiplying through by -1: \[ 6x + 8y = 25 + a^2 \] ### Final Step: Locus Equation Thus, the equation of the locus of the center of the circle is: \[ 6x + 8y = a^2 + 25 \]
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