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The equation of the circle which passes ...

The equation of the circle which passes through the origin, center lies on the line x+y = 4 and cuts the circle `x^2 + y^2 - 4x + 2y +4 = 0` orthogonally :

A

`x ^(2) + y ^(2) - 2x - 6y =0`

B

` x ^(2) + y ^(2) - 6x - 2y =0`

C

`x ^(2) +y ^(2) - 4x - 4y =0`

D

`x ^(2) + y ^(2) - 8x =0`

Text Solution

Verified by Experts

The correct Answer is:
D
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MCGROW HILL PUBLICATION-CIRCLES AND SYSTEMS OF CIRCLES -SOLVED EXAMPLES (LEVEL 1 ( SINGLE CORRECT ANSWER TYPE QUESTIONS ))
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  9. If two circles x ^(2) + y ^(2) + 2gx + 2fy =0 and x ^(2) +y ^(2) + 2g ...

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  14. An equilateral triangle is inscribed in the circle x^2+y^2=a^2 with o...

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  15. Length of the common chord of the circles (x -1) ^(2) + (y + 1)^(2) ...

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