Home
Class 12
MATHS
Equation of the circle on the common cho...

Equation of the circle on the common chord of the circles `x ^(2) + y ^(2) -ax =0 and x ^(2) + y ^(2) - ay =0` as a diameter is

A

`2x ^(2) + 2y ^(2) -ax -ay =0`

B

`x ^(2) +y ^(2) -ax -ay =0`

C

`2x ^(2) + 2y ^(2) + ax + ay=0`

D

`x ^(2) + y ^(2) -x -y + a=0`

Text Solution

AI Generated Solution

The correct Answer is:
To find the equation of the circle on the common chord of the circles \( x^2 + y^2 - ax = 0 \) and \( x^2 + y^2 - ay = 0 \) as a diameter, we can follow these steps: ### Step 1: Write the equations of the circles The given circles can be rewritten as: 1. Circle 1: \( S_1: x^2 + y^2 - ax = 0 \) 2. Circle 2: \( S_2: x^2 + y^2 - ay = 0 \) ### Step 2: Find the equation of the common chord The equation of the common chord of two circles can be found using the formula: \[ S_1 - S_2 = 0 \] Substituting \( S_1 \) and \( S_2 \): \[ (x^2 + y^2 - ax) - (x^2 + y^2 - ay) = 0 \] This simplifies to: \[ -ax + ay = 0 \] Factoring out \( a \): \[ a(y - x) = 0 \] Thus, the equation of the common chord is: \[ x - y = 0 \quad \text{or} \quad y = x \] ### Step 3: Use the common chord as the diameter of a new circle The equation of a circle with diameter along the line \( y = x \) can be expressed in terms of its center and radius. The center of this circle lies on the line \( y = x \). ### Step 4: Find the center of the new circle Let the center of the new circle be \( (h, h) \). The radius of the circle can be determined based on the distance from the center to any point on the line \( y = x \). ### Step 5: Write the equation of the circle The general equation of a circle with center \( (h, h) \) and radius \( r \) is: \[ (x - h)^2 + (y - h)^2 = r^2 \] Since the diameter is along the line \( y = x \), we can use the midpoint of the common chord as the center. ### Step 6: Substitute \( h \) To find the radius, we can note that the radius will be half the length of the common chord. However, since we are looking for the equation of the circle, we can directly express it as: \[ (x - \frac{a}{2})^2 + (y - \frac{a}{2})^2 = \left(\frac{a}{2}\right)^2 \] This leads us to the final equation of the circle. ### Final Equation The equation of the circle on the common chord of the two given circles as a diameter is: \[ x^2 + y^2 - ax - ay + \frac{a^2}{2} = 0 \]
Promotional Banner

Topper's Solved these Questions

  • CIRCLES AND SYSTEMS OF CIRCLES

    MCGROW HILL PUBLICATION|Exercise EXERCISE (LEVEL 1 ( SINGLE CORRECT ANSWER TYPE QUESTIONS ))|53 Videos
  • CIRCLES AND SYSTEMS OF CIRCLES

    MCGROW HILL PUBLICATION|Exercise EXERCISE (LEVEL 2 ( SINGLE CORRECT ANSWER TYPE QUESTIONS ))|30 Videos
  • CIRCLES AND SYSTEMS OF CIRCLES

    MCGROW HILL PUBLICATION|Exercise SOLVED EXAMPLES (NUMERICAL ANSWER TYPE QUESTIONS )|17 Videos
  • CARTESIAN SYSTEM OF RECTANGULAR COORDINATES AND STRAIGHT LINES

    MCGROW HILL PUBLICATION|Exercise QUESTIONS FROM PREVIOUS YEARS. B - ARCHITECTURE (ENTRANCE EXAMINATION PAPERS)|14 Videos
  • COMPLEX NUMBERS

    MCGROW HILL PUBLICATION|Exercise QUESTIONS FROM PREVIOUS YEARS. B-ARCHITECTURE ENTRANCE EXAMINATION PAPER|17 Videos

Similar Questions

Explore conceptually related problems

The equation of the circle described on the common chord of the circles x^(2)+y^(2)-4x-5=0 and x^(2)+y^(2)+8y+7=0 as a diameter,is

The equation of the circle described on the common chord of the circles x^(2)+y^(2)+2x=0 and x^(2)+y^(2)+2y=0 as diameter, is

The equation of the circle on the common chord of the circles (x-a)^(2)+y^(2)=a^(2) and x^(2)+(y+b)^(2)=b^(2) as diameter, is

The length of the common chord of the circles x^(2)+y^(2)-2x-1=0 and x^(2)+y^(2)+4y-1=0 , is

Equation of a common chord of the circles x ^(2) + y ^(2) + 6x -10 y + 9=0 and x ^(2) + y ^(2) - 10 x + 6y + 25=0 is

The lenght of the common chord of circles x^(2)+y^(2)-6x-16=0 and x^(2)+y^(2)-8y-9=0 is

Find the length of the common chord of the circles x^(2)+y^(2)+2x+6y=0 and x^(2)+y^(2)-4x-2y-6=0

MCGROW HILL PUBLICATION-CIRCLES AND SYSTEMS OF CIRCLES -EXERCISE (CONCEPT-BASED ( SINGLE CORRECT ANSWER TYPE QUESTIONS ))
  1. Equation of the circle passing through the origin and having its centr...

    Text Solution

    |

  2. The radius of the circle 3x ^(2) + by ^(2) + 4 bx - 6by + b ^(2) =0 ...

    Text Solution

    |

  3. Find the equaiton of the circle drawn on the intercept between the axe...

    Text Solution

    |

  4. The point (1,2) lies inside and (3,4) outside the circle x ^(2) +y ^(2...

    Text Solution

    |

  5. S: x ^(2) + y ^(2) + 6x - 14y-6 =0 is a circle and L: 7x + 3y + 58 =...

    Text Solution

    |

  6. The angle between the two tangents from the origin to the circle (x-7)...

    Text Solution

    |

  7. A line passes through the point P (5,6) outside the circle x^(2) + y ^...

    Text Solution

    |

  8. The tangent to the circle x^(2)+y^(2)=5 at the point (1, -2) also touc...

    Text Solution

    |

  9. Two circles of equal radius of 5 units have their centres at the origi...

    Text Solution

    |

  10. Two circle touch each other externally at the point (0,k) and y-axis i...

    Text Solution

    |

  11. A circle has radius 3u n i t s and its centre lies on the line y=x-1. ...

    Text Solution

    |

  12. The line 3x -y -17=0 meets the circle x ^(2) +y ^(2) -8x+ 10 y + 5=0 a...

    Text Solution

    |

  13. A circle passes through the origin and has its center on y=x If it cut...

    Text Solution

    |

  14. Equation of the circle on the common chord of the circles x ^(2) + y ^...

    Text Solution

    |

  15. A circle touches the lines x-y- 1 =0 and x -y +1 =0. the centre of the...

    Text Solution

    |

  16. Find the number of common tangents that can be drawn to the circles...

    Text Solution

    |

  17. If the circle (x-2) ^(2) + (y -3) ^(2)=a ^(2) lies entirely in the cir...

    Text Solution

    |

  18. There are four circles each of radius 1 unit touching both the axis. T...

    Text Solution

    |

  19. Find the locus of a point which moves so that the ratio of the lengths...

    Text Solution

    |

  20. A circle has two of its diameters along the lines 2x + 3y - 18 =0 and ...

    Text Solution

    |