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If r.n=q is the equation of a plane norm...

If `r.n=q` is the equation of a plane normal to the vector n, the length of the perpendicular from the origin on the plane is

A

q

B

`|n|`

C

`q|n|`

D

`(q)/(|n|)`

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The correct Answer is:
To find the length of the perpendicular from the origin to the plane given by the equation \( r \cdot n = q \), we can follow these steps: ### Step-by-Step Solution 1. **Understand the Equation of the Plane**: The equation \( r \cdot n = q \) represents a plane where \( r \) is the position vector of a point on the plane, \( n \) is a normal vector to the plane, and \( q \) is a scalar. 2. **Identify the Normal Vector**: The normal vector \( n \) can be expressed in terms of its magnitude. We denote the magnitude of \( n \) as \( |n| \). 3. **Define the Unit Normal Vector**: The unit normal vector \( \hat{n} \) is given by: \[ \hat{n} = \frac{n}{|n|} \] 4. **Length of the Perpendicular**: The length of the perpendicular from the origin to the plane can be represented as \( p \). The formula for the length of the perpendicular from a point to a plane is given by: \[ p = \frac{|r_0 \cdot n - q|}{|n|} \] where \( r_0 \) is the position vector of the point from which we are measuring the perpendicular distance. In this case, \( r_0 \) is the origin, which has coordinates (0, 0, 0), so \( r_0 \cdot n = 0 \). 5. **Substituting Values**: Therefore, substituting into the formula, we have: \[ p = \frac{|0 \cdot n - q|}{|n|} = \frac{| - q |}{|n|} = \frac{q}{|n|} \] 6. **Conclusion**: Thus, the length of the perpendicular from the origin to the plane is: \[ p = \frac{q}{|n|} \]
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