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If the shortest distance between the lines `(x-1)/alpha= (y+1)/-1 =z/1` and `x+y+z+1=0=2x-y+z+3` is `1/sqrt3` then value of `alpha`

A

`-(16)/(19)`

B

`(-19)/(16)`

C

`(32)/(19)`

D

`(19)/(32)`

Text Solution

Verified by Experts

The correct Answer is:
C
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