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The perpendicular distance from the orig...

The perpendicular distance from the origin to the plane containing the two lines, `(x+2)/3=(y-2)/5=(z+5)/7` and `(x-1)/1=(y-4)/4=(z+4)/7` is: (a) `11sqrt6` (b)`11/(sqrt6)` (c) 11 (d) `6sqrt(11)`

A

`11sqrt(6)`

B

`11//sqrt(6)`

C

11

D

`6sqrt(11)`

Text Solution

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The correct Answer is:
B
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The perpendicular distance from the origin to the plane containing the two lines,(x+2)/(3)=(y-2)/(5)=(z+5)/(7) and (x-1)/(1)=(y-4)/(4)=(z+4)/(7) is: (a) 11sqrt(6)(b)(11)/(sqrt(6))(c)11(d)6sqrt(11)

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If the distance between the plane Ax-2y+z=d .and the plane containing the lies (x+1)/(2)=(y-2)/(3)=(z-3)/(4) and (x-2)/(3)=(4-3)/(4)=(z-4)/(5) is sqrt(6), then |d| is

If the distance between the plane Ax-2y+z=d and the plane containing the lines (x-1)/(2)=(y-2)/(3)=(z-3)/(4) and (x-2)/(3)=(y-3)/(4)=(z-4)/(5) is sqrt(6) , then |d| is equal to….

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