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An organic compound undergoes first orde...

An organic compound undergoes first order decomposition. The time taken for its decomposition to 1/8 and 1/10 of its initial concentration are `t_(1/8)` and `t_(1//10)` respectively. What is the value of
`([t_(1//8)])/([t_(1//10)])xx10`? `(log_(10)2=0.3)`

Text Solution

Verified by Experts

The correct Answer is:
9
`(Kxxt_(1/8))/(Kxxt_(1/10))=(2.303xxltg((C_(0))/(C_(0)//8)))/(2.303xxlog((C_(0))/(C_(0)//10))),((t_(1/2))/(t_(1/10)))=(log_(8))/(log_(10)^(10))=(3xxlog2)/1=3xx0.3010=0.9,((t_(1/8))/(t_(1/10)))=10x0.910=9`
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