Home
Class 12
CHEMISTRY
A first order reaction is completed by 2...

A first order reaction is completed by 20% 2 minutes. How much further time is required for 64% of the initial concentration of the reactants to remain.

Text Solution

Verified by Experts

The correct Answer is:
4
`(Kxx2)/(Kxxt)=(log(100/80))/(log(100/64)),2/t=(log1.25)/(log1.5625)=0.0969/0.19382=t=(2xx0.19382)/(0.0969~=4`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    AAKASH SERIES|Exercise PRACTICE SHEET-2 (SINGLE OR MORE THAN ONE OPTION QUESTIONS)|16 Videos

  • CHEMICAL KINETICS

    AAKASH SERIES|Exercise PRACTICE SHEET-2 (LINKED COMPRHENSION TYPE QUESTIONS)|6 Videos

  • CHEMICAL KINETICS

    AAKASH SERIES|Exercise PRACTICE SHEET-1 (MATCH THE FOLLOWING QUESTIONS)|2 Videos

  • CHEMICAL KINETCS

    AAKASH SERIES|Exercise EXERCISE - 3.2|45 Videos

  • CHEMICAL THERMODYNAMICS

    AAKASH SERIES|Exercise Additional Practice Exercise|54 Videos

Similar Questions

Explore conceptually related problems

20% first order reaction is completed in 50 minute. Time required for the completion of 60% of the reaction is

A first order reaction is half completed is 45 minutes. How long does it need for 99.9% of the reaction tobe completed?

A first order reaction is 20% complete in 10 min. How long it takes to complete 80% ?

75% of a first order reaction completed in 32 minutes then, the time required to complete 99.9% of a reaction in seconds is

The rate constant for a first order reaction is 60 s^(-1). How much time will it take to reduce the initial concentration of the reactant to its 1//6^(th) value ?