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A drop of a solution (v=0.05ml) contains...

A drop of a solution (v=0.05ml) contains `6xx10^(-7)` moles of `H^(+)`. If the rate constant of disappearance of `H^(+)` is `6xx10^(5)` mole `L^(-1)S^(-1)` it takes `X xx 10^(-8)s` for `H^(+)` in the drop to disappear X is

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The correct Answer is:
2
`(C_(0)-C_(t))=Kxxt`
`[1.2xx10^(-2)" "-0]=6xx10^(5)(x xx10^(-8)),x=2`
`AtoB`
`1" "0`
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